Budding Developers

 Hello, budding developers. As the title says it all. We will write a program to find the gcd and lcm of two given numbers. Editor used: CodeBlocks Language used: C++ Program: #include <iostream> using namespace std; int main() {     int n1,n2,gcd=0,lcm=0;    cout<<"Enter number 1:";    cin>>n1;    cout<<"\nEnter number 2:";    cin>>n2;      int mult=n1*n2;    while(n1!=n2)    {        if(n1>n2)        {            n1=n1-n2;            gcd=n1;        }        else        {            n2=n2-n1;      ...

Hello, budding developers. As the topic says it all. We will write a program which will take 4 digits and rearrange those digits to give the smallest 4 digit and largest 4 digit number. It should be a valid 4 digit number eg.1000 and not 0001. Editor used: CodeBlocks Language used: C++ Program: #include<iostream> using namespace std; int main() { int arr[4],arr2[4]; int temp=0; cout<<"Enter 4 digits:\n"; for(int i=0;i<4;i++) { cin>>arr[i]; arr2[i]=arr[i]; } for(int i=0;i<4;i++) { for(int j=0;j<4-i;j++) { if(arr[j]>arr[j+1]) { temp=arr[j]; arr[j]=arr[j+1]; arr[j+1]=temp; }}} for(int i=0;i<4;i++) { for(int j=0;j<4-i;j++) { if(arr2[j]<arr2[j+1]) { temp=arr2[j]; arr2[j]=arr2[j+1]; arr2[j+1]=temp; }}} if(arr[0]==0) { temp=arr[0]; arr[0]=arr[1]; arr[1]=temp; } if(arr[0]==0 && arr[1]==0) { temp=arr[0]; arr[0]=arr[2]; arr[2]=temp; } if(arr[0]==0 && arr[1]==0 && arr[2]==0) { temp=arr[0]; arr[0]=arr[3]; arr[3]=temp; } cout...